Ham Radio General Class Practice Test

Disable ads (and more) with a membership for a one time $2.99 payment

Boost your ham radio knowledge with our engaging questions and detailed explanations. Prepare effectively with our diverse study resources. Ready to ace the General Class exam?

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts?

84.8 volts
169.7 volts
240.0 volts
339.4 volts

The correct answer is: 339.4 volts

The peak-to-peak voltage of a sine wave is calculated using the relationship between RMS (root mean square) voltage and peak voltage. The RMS voltage is a measure of the effective value of a varying voltage, while the peak voltage is the maximum voltage in the sine wave cycle. For a sine wave, the relationship between the peak voltage (V_peak) and the RMS voltage (V_rms) can be expressed with the formula: V_peak = V_rms × √2. To find the peak voltage when the RMS voltage is 120 volts, you would calculate: V_peak = 120 volts × √2 ≈ 120 volts × 1.414 = 169.7 volts. The peak-to-peak voltage (V_pp) is double the peak voltage, thus: V_pp = 2 × V_peak = 2 × 169.7 volts = 339.4 volts. This calculation shows how the peak-to-peak voltage is derived from the RMS voltage of the sine wave. In this case, the peak-to-peak voltage of a sine wave with an RMS of 120 volts is indeed 339.4 volts, making that the correct choice.