Ham Radio General Class Test 2026 – 400 Free Practice Questions to Pass the Exam

To determine the output PEP (Peak Envelope Power) of a transmitter based on the given peak-to-peak voltage measurement, we will utilize the formula related to power in a resistive load.

First, we need to convert the peak-to-peak voltage (Vpp) to the RMS (root mean square) voltage, which can then be used to calculate power. For a sine wave, the relationship between peak-to-peak voltage and RMS voltage is given by:

\[ V_{RMS} = \frac{V_{pp}}{2\sqrt{2}} \]

In this case, given that the voltage measured is 500 volts peak-to-peak, the RMS voltage calculation will be:

\[ V_{RMS} = \frac{500 V}{2\sqrt{2}} \approx 176.78 V \]

Next, we calculate the power using the formula for power in a resistive load:

\[ P = \frac{V_{RMS}^2}{R} \]

Where \( R \) is the resistance, which in this scenario is 50 ohms. Plugging in the values we have:

\[ P = \frac{(176.78 V)^2}{50 \Omega